Class 9 Reflection of Light Mock Test (ICSE)

Topics in Reflection of Light

• Laws of reflection
• Images formed by a plane mirror and by inclined mirrors
• Spherical mirrors: focus, centre of curvature and f = R/2
• Image formation by concave and convex mirrors
• Mirror formula and magnification
• Uses of spherical mirrors

Reflection of Light practice questions with answers

1. Q1Multiple choice·1 mark
   A concave mirror produces a real image of height $3\text{ cm}$ of an object of height $1\text{ cm}$ placed in front of it. The magnification produced is:

   1. (a)$-\frac{1}{3}$
   2. (b)$+\frac{1}{3}$
   3. (c)$-3$
   4. (d)$+3$
   Show answer and step marks

   1. Correct option: (c) $-3$+1

   Answer: (c)
2. Q2Multiple choice·1 mark
   An object is placed at a distance of $15\text{ cm}$ in front of a concave mirror of focal length $10\text{ cm}$. The nature of the image formed is:

   1. (a)Virtual and erect
   2. (b)Real and diminished
   3. (c)Virtual and magnified
   4. (d)Real and magnified
   Show answer and step marks

   1. Correct option: (d) Real and magnified+1

   Answer: (d)
3. Q3Multiple choice·1 mark
   Two plane mirrors are inclined at an angle of $60^\circ$ to each other. The number of images formed of an object placed symmetrically between them is:

   1. (a)3
   2. (b)5
   3. (c)4
   4. (d)6
   Show answer and step marks

   1. Correct option: (b) $5$+1

   Answer: (b)
4. Q4Multiple choice·1 mark
   The radius of curvature of a convex mirror is $40\text{ cm}$. Its focal length is:

   1. (a)$-40\text{ cm}$
   2. (b)$+20\text{ cm}$
   3. (c)$+40\text{ cm}$
   4. (d)$-20\text{ cm}$
   Show answer and step marks

   1. Correct option: (b) $+20\text{ cm}$+1

   Answer: (b)
5. Q5Long answer·4 marks
   (a) State the two laws of reflection of light. (b) A ray of light is incident on a plane mirror at an angle of $40^\circ$ with the reflecting surface. Calculate: (i) The angle of incidence. (ii) The angle of deviation of the ray.
   Show answer and step marks

   1. First law: The incident ray, the reflected ray, and the normal at the point of incidence all lie in the same plane.+1
   2. Second law: The angle of incidence is equal to the angle of reflection.+1
   3. (i) Angle of incidence $i = 90^\circ - 40^\circ = 50^\circ$.+1
   4. (ii) Angle of deviation $\delta = 180^\circ - 2i = 180^\circ - 2(50^\circ) = 80^\circ$.+1

   Answer: (a) The incident ray, the reflected ray and the normal at the point of incidence all lie in the same plane; the angle of incidence is equal to the angle of reflection. (b)(i) $50^\circ$, (b)(ii) $80^\circ$.

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