ICSE · Class 9 · Physics

Class 9 Pressure in Fluids and Atmospheric Pressure Mock Test (ICSE)

6 practice questions from Pressure in Fluids and Atmospheric Pressure, in the style of your board paper, each with a worked answer and the marks for every step. Then take a full chapter test on paper, snap the pages and get every step marked.

Topics in Pressure in Fluids and Atmospheric Pressure

  • Thrust and pressure
  • Pressure in a liquid column (p = h rho g)
  • Pascal's law and the hydraulic machine
  • Atmospheric pressure and its measurement
  • Variation of atmospheric pressure with altitude

Pressure in Fluids and Atmospheric Pressure practice questions with answers

  1. Q1Multiple choice1 mark
    As we ascend to a higher altitude, how does the atmospheric pressure change?
    1. (a)It first decreases and then increases due to temperature variation.
    2. (b)It remains constant because air pressure is independent of altitude.
    3. (c)It increases because air density increases.
    4. (d)It decreases because the height of the air column above decreases.
    Show answer and step marks
    1. Correct option: (d) It decreases because the height of the air column above decreases.+1
    Answer: (d)
  2. Q2Multiple choice1 mark
    The pressure at a depth hh in a liquid of density ρ\rho is given by p=hρgp = h\rho g. On what factor does the liquid pressure NOT depend?
    1. (a)Surface area of the liquid container
    2. (b)Depth of the point inside the liquid
    3. (c)Density of the liquid
    4. (d)Acceleration due to gravity
    Show answer and step marks
    1. Correct option: (a) Surface area of the liquid container+1
    Answer: (a)
  3. Q3Multiple choice1 mark
    A force of 100 N100 \text{ N} is applied normally on a surface of area 2 m22 \text{ m}^2. The pressure exerted on the surface is:
    1. (a)50 N/m250 \text{ N/m}^2
    2. (b)100 N/m2100 \text{ N/m}^2
    3. (c)0.02 N/m20.02 \text{ N/m}^2
    4. (d)200 N/m2200 \text{ N/m}^2
    Show answer and step marks
    1. Correct option: (a) 50 N/m250 \text{ N/m}^2+1
    Answer: (a)
  4. Q4Multiple choice1 mark
    Which of the following instruments is commonly used for weather forecasting to measure atmospheric pressure without the use of any liquid?
    1. (a)Simple barometer
    2. (b)Aneroid barometer
    3. (c)Fortin's barometer
    4. (d)Manometer
    Show answer and step marks
    1. Correct option: (b) Aneroid barometer+1
    Answer: (b)
  5. Q5Short answer2 marks
    State Pascal's law of transmission of pressure in liquids. Mention one practical application based on it.
    Show answer and step marks
    1. Statement: Pressure exerted anywhere in a confined liquid is transmitted equally and undiminished in all directions throughout the liquid.+1
    2. Application, any one of: hydraulic press; hydraulic lift (jack); hydraulic brakes of vehicles; or any other valid hydraulic machine.+1
    Answer: Pressure applied at any point of a liquid enclosed in a vessel is transmitted equally and undiminished in all directions. Application, any one of: hydraulic press, hydraulic lift (jack), hydraulic brakes.
  6. Q6Long answer4 marks
    (a) Define standard atmospheric pressure and state its value in SI units. [2] (b) Calculate the pressure exerted by a vertical mercury column of height 76 cm76 \text{ cm}. Take the density of mercury as 1.36×104 kg/m31.36 \times 10^4 \text{ kg/m}^3 and acceleration due to gravity g=9.8 m/s2g = 9.8 \text{ m/s}^2. [2]
    Show answer and step marks
    1. Definition: Standard atmospheric pressure is the pressure exerted by a mercury column of height 76 cm76\text{ cm} at 0∘C0^{\circ}\text{C} at sea level.+1
    2. Value in SI units: 1.013×105 Pa1.013 \times 10^5 \text{ Pa} (or N/m2\text{N/m}^2).+1
    3. Formula for pressure: p=hρgp = h\rho g, where h=0.76 mh = 0.76\text{ m}, ρ=1.36×104 kg/m3\rho = 1.36 \times 10^4\text{ kg/m}^3, and g=9.8 m/s2g = 9.8\text{ m/s}^2.+1
    4. Substitution and calculation: p=0.76×1.36×104×9.8=1.013×105 Pap = 0.76 \times 1.36 \times 10^4 \times 9.8 = 1.013 \times 10^5 \text{ Pa}.+1
    Answer: (a) Standard atmospheric pressure is the pressure exerted by a 76 cm76\text{ cm} column of mercury at 0∘C0^{\circ}\text{C} at sea level; its value is 1.013×105 Pa1.013 \times 10^5\text{ Pa}. (b) p=hρg=0.76×1.36×104×9.8=1.013×105 Pap = h\rho g = 0.76 \times 1.36 \times 10^4 \times 9.8 = 1.013 \times 10^5\text{ Pa}.

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