ICSE · Class 9 · Physics

Class 9 Motion in One Dimension Mock Test (ICSE)

6 practice questions from Motion in One Dimension, in the style of your board paper, each with a worked answer and the marks for every step. Then take a full chapter test on paper, snap the pages and get every step marked.

Topics in Motion in One Dimension

  • Scalars and vectors
  • Distance and displacement
  • Speed, velocity and acceleration
  • Distance-time and velocity-time graphs
  • Equations of uniformly accelerated motion
  • Motion under gravity

Motion in One Dimension practice questions with answers

  1. Q1Multiple choice1 mark
    A body starts from rest and accelerates uniformly at 2 m/s22\text{ m/s}^2 for 5 s5\text{ s}. The distance travelled by the body in this time is:
    1. (a)10 m10\text{ m}
    2. (b)25 m25\text{ m}
    3. (c)100 m100\text{ m}
    4. (d)50 m50\text{ m}
    Show answer and step marks
    1. Correct option: (b) 25 m25\text{ m}+1
    Answer: (b)
  2. Q2Multiple choice1 mark
    A car moving along a straight road has its speed reduced steadily from 20 m/s to 5 m/s. Which statement correctly describes its acceleration?
    1. (a)Zero, since the car is still moving along the road
    2. (b)Positive, since the car is still moving forward
    3. (c)Positive, since the speed is changing with time
    4. (d)Negative, since the velocity is decreasing in the direction of motion
    Show answer and step marks
    1. Correct option: (d) Negative, since the velocity is decreasing in the direction of motion+1
    Answer: (d)
  3. Q3Multiple choice1 mark
    A student walks 4 m east and then 3 m west along a straight road. Which pair of values correctly gives the distance covered and the displacement of the student?
    1. (a)Distance 1 m; displacement 7 m east
    2. (b)Distance 7 m; displacement 1 m east
    3. (c)Distance 1 m; displacement 1 m east
    4. (d)Distance 7 m; displacement 7 m east
    Show answer and step marks
    1. Correct option: (b) Distance 7 m; displacement 1 m east+1
    Answer: (b)
  4. Q4Multiple choice1 mark
    In a hospital corridor, a wheelchair is pushed along a straight path. Its distance-time graph is a horizontal straight line for a short interval. What does this part of the graph show?
    1. (a)The wheelchair is at rest
    2. (b)The wheelchair moves with uniform speed
    3. (c)The wheelchair moves with uniform acceleration
    4. (d)The wheelchair has turned back to its starting point
    Show answer and step marks
    1. Correct option: (a) The wheelchair is at rest+1
    Answer: (a)
  5. Q5Multiple choice1 mark
    A stone is thrown vertically upwards with an initial velocity uu and reaches a maximum height hh. If air resistance is neglected, the time taken by the stone to reach the highest point is given by:
    1. (a)u22g\frac{u^2}{2g}
    2. (b)2ug\frac{2u}{g}
    3. (c)hu\frac{h}{u}
    4. (d)ug\frac{u}{g}
    Show answer and step marks
    1. Correct option: (d) ug\frac{u}{g}+1
    Answer: (d)
  6. Q6Long answer4 marks
    A train moving with a uniform velocity of 54 km/h54\text{ km/h} is brought to rest with uniform retardation in 15 s15\text{ s} by applying brakes. (a) Calculate the retardation produced in the train. (b) Find the distance covered by the train before coming to rest.
    Show answer and step marks
    1. Initial velocity u=54 km/h=54×518=15 m/su = 54\text{ km/h} = 54 \times \frac{5}{18} = 15\text{ m/s}+1
    2. Retardation a=v−ut=0−1515=−1 m/s2a = \frac{v - u}{t} = \frac{0 - 15}{15} = -1\text{ m/s}^2, so retardation is 1 m/s21\text{ m/s}^2+1
    3. Substitution in distance formula s=ut+12at2s = ut + \frac{1}{2}at^2, s=15×15+12(−1)(15)2s = 15 \times 15 + \frac{1}{2}(-1)(15)^2+1
    4. Distance covered s=225−112.5=112.5 ms = 225 - 112.5 = 112.5\text{ m}+1
    Answer: Retardation = 1 m/s21\text{ m/s}^2, Distance = 112.5 m112.5\text{ m}

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  • 15 min10 marks
  • 30 min20 marks
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  • 3 hr80 marks
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