ICSE · Class 9 · Mathematics

Class 9 Rectilinear Figures (Quadrilaterals and Polygons) Mock Test (ICSE)

4 practice questions from Rectilinear Figures (Quadrilaterals and Polygons), in the style of your board paper, each with a worked answer and the marks for every step. Then take a full chapter test on paper, snap the pages and get every step marked.

Topics in Rectilinear Figures (Quadrilaterals and Polygons)

  • Sum of interior and exterior angles of a polygon
  • Regular polygons
  • Properties of parallelogram, rectangle, rhombus and square
  • Proofs on quadrilaterals

Rectilinear Figures (Quadrilaterals and Polygons) practice questions with answers

  1. Q1Multiple choice1 mark
    If the diagonals of a rhombus are 12 cm12\text{ cm} and 16 cm16\text{ cm}, then the length of its side is:
    1. (a)14 cm
    2. (b)8 cm
    3. (c)10 cm
    4. (d)20 cm
    Show answer and step marks
    1. Correct option: (c) Side of rhombus s=(d12)2+(d22)2=62+82=100=10 cms = \sqrt{\left(\frac{d_1}{2}\right)^2 + \left(\frac{d_2}{2}\right)^2} = \sqrt{6^2 + 8^2} = \sqrt{100} = 10\text{ cm}.+1
    Answer: (c)
  2. Q2Multiple choice1 mark
    The sum of the interior angles of a regular polygon is 1080∘1080^\circ. The number of sides of the polygon is:
    1. (a)66
    2. (b)1010
    3. (c)77
    4. (d)88
    Show answer and step marks
    1. Correct option: (d) 88+1
    Answer: (d)
  3. Q3Multiple choice1 mark
    If the diagonals of a parallelogram are equal and bisect each other at right angles, then the most specific name for the quadrilateral is:
    1. (a)Rectangle
    2. (b)Rhombus
    3. (c)Square
    4. (d)Kite
    Show answer and step marks
    1. Correct option: (c) Square. Equal diagonals make it a rectangle and perpendicular diagonals make it a rhombus, so it is a square.+1
    Answer: (c)
  4. Q4Long answer4 marks
    The measure of each interior angle of a regular polygon is 55 times the measure of its exterior angle. (a) Find the measure of each exterior angle and each interior angle. (b) Find the number of sides of the polygon. (c) Find the sum of all the interior angles of this polygon.
    Show answer and step marks
    1. Let the exterior angle of the regular polygon be xx. Then the interior angle is 5x5x. Since the interior and exterior angles are supplementary, x+5x=180∘x + 5x = 180^\circ.+1
    2. Solving for xx, 6x=180∘  ⟹  x=30∘6x = 180^\circ \implies x = 30^\circ, so the exterior angle is 30∘30^\circ.+0.5
    3. The interior angle is 5×30∘=150∘5 \times 30^\circ = 150^\circ.+0.5
    4. The number of sides nn is given by n=360∘Exterior angle=360∘30∘=12n = \frac{360^\circ}{\text{Exterior angle}} = \frac{360^\circ}{30^\circ} = 12.+1
    5. The sum of all interior angles =(n−2)×180∘=(12−2)×180∘=10×180∘=1800∘= (n - 2) \times 180^\circ = (12 - 2) \times 180^\circ = 10 \times 180^\circ = 1800^\circ.+1
    Answer: Exterior angle: 30∘30^\circ, Interior angle: 150∘150^\circ, Number of sides: 1212, Sum of interior angles: 1800∘1800^\circ

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