ICSE · Class 9 · Mathematics

Class 9 Mean and Median Mock Test (ICSE)

4 practice questions from Mean and Median, in the style of your board paper, each with a worked answer and the marks for every step. Then take a full chapter test on paper, snap the pages and get every step marked.

Topics in Mean and Median

  • Mean of ungrouped data
  • Mean of ungrouped frequency distribution
  • Median of ungrouped data
  • Properties of mean

Mean and Median practice questions with answers

  1. Q1Multiple choice1 mark
    If the mean of the following distribution is 44, find the value of pp. xx: 2,4,6,82, 4, 6, 8 ff: 3,2,p,13, 2, p, 1
    1. (a)11
    2. (b)44
    3. (c)33
    4. (d)22
    Show answer and step marks
    1. Correct option: (a) 11. Using Mean=∑fixi∑fi\text{Mean} = \frac{\sum f_i x_i}{\sum f_i}, we get 2(3)+4(2)+6(p)+8(1)3+2+p+1=4\frac{2(3) + 4(2) + 6(p) + 8(1)}{3 + 2 + p + 1} = 4, which simplifies to 6+8+6p+86+p=4  ⟹  22+6p6+p=4  ⟹  22+6p=24+4p  ⟹  2p=2  ⟹  p=1\frac{6 + 8 + 6p + 8}{6 + p} = 4 \implies \frac{22 + 6p}{6 + p} = 4 \implies 22 + 6p = 24 + 4p \implies 2p = 2 \implies p = 1.+1
    Answer: (a)
  2. Q2Multiple choice1 mark
    Find the mean of the first five prime numbers.
    1. (a)4.84.8
    2. (b)5.65.6
    3. (c)5.25.2
    4. (d)6.06.0
    Show answer and step marks
    1. Correct option: (b) 5.65.6. The first five prime numbers are 2,3,5,7,112, 3, 5, 7, 11, and their mean is 2+3+5+7+115=285=5.6\frac{2 + 3 + 5 + 7 + 11}{5} = \frac{28}{5} = 5.6.+1
    Answer: (b)
  3. Q3Multiple choice1 mark
    If each observation of a set of data is increased by 55, then the mean of the new observations:
    1. (a)is increased by 55
    2. (b)is multiplied by 55
    3. (c)remains unchanged
    4. (d)is divided by 55
    Show answer and step marks
    1. Correct option: (a) is increased by 55. By the properties of mean, if a constant cc is added to each observation, the mean also increases by cc.+1
    Answer: (a)
  4. Q4Multiple choice1 mark
    The median of the observations 11,12,14,18,x+2,x+4,30,32,35,4111, 12, 14, 18, x+2, x+4, 30, 32, 35, 41 arranged in ascending order is 2424. Find the value of xx.
    1. (a)2222
    2. (b)2121
    3. (c)1919
    4. (d)2020
    Show answer and step marks
    1. Correct option: (b) 2121. Since n=10n = 10 (even), the median is the average of the 5th and 6th terms: (x+2)+(x+4)2=24  ⟹  2x+6=48  ⟹  2x=42  ⟹  x=21\frac{(x+2) + (x+4)}{2} = 24 \implies 2x + 6 = 48 \implies 2x = 42 \implies x = 21.+1
    Answer: (b)

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