ICSE · Class 9 · Mathematics

Class 9 Compound Interest Mock Test (ICSE)

5 practice questions from Compound Interest, in the style of your board paper, each with a worked answer and the marks for every step. Then take a full chapter test on paper, snap the pages and get every step marked.

Topics in Compound Interest

  • Compound interest year by year
  • Interest compounded half-yearly
  • Finding principal or rate step by step
  • Amount using formula
  • Compound interest when rate varies each year
  • Growth and depreciation
  • Finding rate, time or principal

Compound Interest practice questions with answers

  1. Q1Multiple choice1 mark
    If the compound interest on a certain sum for the first year is ₹ 400400 and for the second year is ₹ 440440, the rate of interest per annum is:
    1. (a)10%10\%
    2. (b)12%12\%
    3. (c)8%8\%
    4. (d)5%5\%
    Show answer and step marks
    1. Correct option: (a) 10%10\%. The extra interest in the second year (₹ 440−440 - ₹ 400=400 = ₹ 4040) is the interest on the first year's interest of ₹ 400400 for 11 year. Thus, rate = 40×100400×1=10%\frac{40 \times 100}{400 \times 1} = 10\%.+1
    Answer: (a)
  2. Q2Multiple choice1 mark
    The compound interest on ₹ 40004000 at 10%10\% per annum for 22 years, compounded annually, is:
    1. (a)₹ 880880
    2. (b)₹ 800800
    3. (c)₹ 840840
    4. (d)₹ 820820
    Show answer and step marks
    1. Correct option: (c) ₹ 840840. Interest for 1st year = 4000×10×1100=\frac{4000 \times 10 \times 1}{100} = ₹ 400400. Amount after 1st year = ₹ 4000+4000 + ₹ 400=400 = ₹ 44004400. Interest for 2nd year = 4400×10×1100=\frac{4400 \times 10 \times 1}{100} = ₹ 440440. Total compound interest = ₹ 400+400 + ₹ 440=440 = ₹ 840840.+1
    Answer: (c)
  3. Q3Multiple choice1 mark
    A sum of ₹ 50005000 is borrowed at 20%20\% per annum compound interest. If the interest is compounded half-yearly, the amount to be paid after 66 months is:
    1. (a)₹ 54005400
    2. (b)₹ 55005500
    3. (c)₹ 56005600
    4. (d)₹ 60006000
    Show answer and step marks
    1. Correct option: (b) ₹ 55005500. For 66 months compounded half-yearly, time is 11 half-year and rate is 20%2=10%\frac{20\%}{2} = 10\% per half-year. Interest = 5000×10×1100=\frac{5000 \times 10 \times 1}{100} = ₹ 500500. Amount = ₹ 5000+5000 + ₹ 500=500 = ₹ 55005500.+1
    Answer: (b)
  4. Q4Multiple choice1 mark
    Find the compound interest on ₹ 60006000 for 11 year at 10%10\% per annum compounded half-yearly.
    1. (a)₹ 615.15615.15
    2. (b)₹ 630630
    3. (c)₹ 615615
    4. (d)₹ 600600
    Show answer and step marks
    1. Correct option: (c) ₹ 615615. Interest for the first half-year = 6000×5×1100=\frac{6000 \times 5 \times 1}{100} = ₹ 300300, making the amount ₹ 63006300. Interest for the second half-year = 6300×5×1100=\frac{6300 \times 5 \times 1}{100} = ₹ 315315. Total compound interest = 300+315=300 + 315 = ₹ 615615.+1
    Answer: (c)
  5. Q5Long answer4 marks
    Calculate the compound interest on ₹ 1250012500 for 22 years at 8%8\% per annum, compounded yearly, by calculating the interest year by year without using the direct formula. Also, find the total amount at the end of 22 years.
    Show answer and step marks
    1. Interest for the first year = 12500×8×1100=₹ 1000\frac{12500 \times 8 \times 1}{100} = \text{₹ } 1000+1
    2. Amount at the end of the first year (Principal for the second year) = ₹ 12500+₹ 1000=₹ 1350012500 + \text{₹ } 1000 = \text{₹ } 13500+0.5
    3. Interest for the second year = 13500×8×1100=₹ 1080\frac{13500 \times 8 \times 1}{100} = \text{₹ } 1080+1
    4. Total Compound Interest = ₹ 1000+₹ 1080=₹ 2080\text{₹ } 1000 + \text{₹ } 1080 = \text{₹ } 2080+1
    5. Total Amount = ₹ 13500+₹ 1080=₹ 14580\text{₹ } 13500 + \text{₹ } 1080 = \text{₹ } 14580+0.5
    Answer: Compound Interest = ₹ 20802080, Total Amount = ₹ 1458014580

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