CBSE · Class 9 · Science

Class 9 Journey Inside the Atom Mock Test (CBSE)

6 practice questions from Journey Inside the Atom, in the style of your board paper, each with a worked answer and the marks for every step. Then take a full chapter test on paper, snap the pages and get every step marked.

Topics in Journey Inside the Atom

  • Roots of atomic theory
  • Thomson's model of the atom
  • Gold foil experiment
  • Bohr's model of the atom
  • Discovery of the neutron
  • Symbols of elements
  • Atomic number and mass number
  • Distribution of electrons in energy levels
  • Valency
  • Isotopes and average atomic mass
  • Isobars

Journey Inside the Atom practice questions with answers

  1. Q1Multiple choice1 mark
    An element has an atomic number of 1212. What is the number of valence electrons present in an atom of this element?
    1. (a)11
    2. (b)22
    3. (c)66
    4. (d)88
    Show answer and step marks
    1. Correct option: (b) 22. The electronic configuration for atomic number 1212 is 2,8,22, 8, 2, which means there are 22 electrons in the outermost shell.+1
    Answer: (b)
  2. Q2Assertion and reason1 mark
    Assertion (A): The maximum number of electrons that can be accommodated in any energy level is given by the formula 2n22n^2, where nn is the orbit number. Reason (R): The maximum number of electrons in the outermost shell is 88, even if it can hold more according to the 2n22n^2 formula.
    1. (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
    2. (b)Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).
    3. (c)Assertion (A) is true but Reason (R) is false.
    4. (d)Assertion (A) is false but Reason (R) is true.
    Show answer and step marks
    1. Correct option: (b) Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).+1
    Answer: (b)
  3. Q3Multiple choice1 mark
    An element has an atomic number of 1717 and a mass number of 3535. The number of neutrons in its neutral atom is:
    1. (a)17
    2. (b)18
    3. (c)35
    4. (d)52
    Show answer and step marks
    1. Correct option: (b) 18. Number of neutrons = Mass number - Atomic number = 35−17=1835 - 17 = 18.+1
    Answer: (b)
  4. Q4Assertion and reason1 mark
    Assertion (A): Isotopes of an element have identical chemical properties. Reason (R): Chemical properties of an atom are controlled by the number of electrons, which is determined by the atomic number, and isotopes have the same atomic number.
    1. (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
    2. (b)Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).
    3. (c)Assertion (A) is true but Reason (R) is false.
    4. (d)Assertion (A) is false but Reason (R) is true.
    Show answer and step marks
    1. Correct option: (a) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).+1
    Answer: (a)
  5. Q5Short answer3 marks
    Define isotopes. An element XX has two naturally occurring isotopes 1735X{}^{35}_{17}X and 1737X{}^{37}_{17}X in the percentage abundance of 75%75\% and 25%25\% respectively. Calculate the average atomic mass of element XX.
    Show answer and step marks
    1. Define isotopes as atoms of the same element having the same atomic number but different mass numbers.+1
    2. Set up the average atomic mass formula: Average Mass=(35×75)+(37×25)100\text{Average Mass} = \frac{(35 \times 75) + (37 \times 25)}{100}.+1
    3. Calculate the final value: 2625+925100=35.5 u\frac{2625 + 925}{100} = 35.5\text{ u}.+1
    Answer: Isotopes are atoms of the same element having the same atomic number but different mass numbers. Average atomic mass of XX = 35.5 u35.5\text{ u}.
  6. Q6Long answer5 marks
    (a) Define isotopes. Give two distinct practical applications or uses of isotopes in various fields. (b) An element XX has an atomic number of 1717 and a mass number of 3535. Determine: (i) The number of protons, neutrons, and electrons in atom XX. (ii) The electronic configuration of XX and its valency.
    Show answer and step marks
    1. Definition of isotopes: Atoms of the same element having the same atomic number but different mass numbers.+1
    2. First use of isotopes, any one of: cobalt-60 in the treatment of cancer; iodine-131 in the treatment of goitre; uranium-235 as fuel in nuclear reactors; carbon-14 in dating old objects; or any other valid use.+0.5
    3. Second use, a different one from the same list.+0.5
    4. Number of protons = 1717 (equal to the atomic number).+0.5
    5. Number of electrons = 1717 (neutral atom).+0.5
    6. Number of neutrons = 35−17=1835 - 17 = 18.+0.5
    7. Electronic configuration of XX: 2,8,72, 8, 7 (K, L, M shells respectively).+1
    8. Valency of XX: it needs 11 electron to complete its octet, so its valency is 11.+0.5
    Answer: (a) Isotopes are atoms of the same element with the same atomic number but different mass numbers. Any two of: cobalt-60 to treat cancer; iodine-131 to treat goitre; uranium-235 as nuclear-reactor fuel; carbon-14 for dating old objects. (b)(i) Protons 17, neutrons 18, electrons 17. (ii) Configuration 2, 8, 7; valency 1.

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