CBSE · Class 9 · Mathematics

Class 9 Math of Space: Surface Area and Volume Mock Test (CBSE)

6 practice questions from Math of Space: Surface Area and Volume, in the style of your board paper, each with a worked answer and the marks for every step. Then take a full chapter test on paper, snap the pages and get every step marked.

Topics in Math of Space: Surface Area and Volume

  • Surface area and volume of cuboids and cubes
  • Surface area and volume of a right circular cylinder
  • Surface area and volume of a right circular cone
  • Pyramids
  • Surface area and volume of a sphere
  • Hemispheres
  • Guesstimates: estimating areas and volumes around us

Math of Space: Surface Area and Volume practice questions with answers

  1. Q1Multiple choice1 mark
    If the radius of a sphere is doubled, its surface area becomes how many times the original surface area?
    1. (a)8 times
    2. (b)4 times
    3. (c)16 times
    4. (d)2 times
    Show answer and step marks
    1. Correct option: (b) 44 times+1
    Answer: (b)
  2. Q2Multiple choice1 mark
    The radius of the base of a right circular cylinder is 7 cm7\text{ cm} and its height is 10 cm10\text{ cm}. What is the curved surface area of the cylinder? (Use π=227\pi = \frac{22}{7})
    1. (a)440 cm2440\text{ cm}^2
    2. (b)880 cm2880\text{ cm}^2
    3. (c)1540 cm21540\text{ cm}^2
    4. (d)220 cm2220\text{ cm}^2
    Show answer and step marks
    1. Correct option: (a) 440 cm2440\text{ cm}^2. Curved surface area of a cylinder = 2πrh=2×227×7×10=440 cm22\pi rh = 2 \times \frac{22}{7} \times 7 \times 10 = 440\text{ cm}^2.+1
    Answer: (a)
  3. Q3Multiple choice1 mark
    The total surface area of a solid hemisphere of radius rr is given by:
    1. (a)3πr23\pi r^2
    2. (b)6πr26\pi r^2
    3. (c)2πr22\pi r^2
    4. (d)4πr24\pi r^2
    Show answer and step marks
    1. Correct option: (a) 3πr23\pi r^2+1
    Answer: (a)
  4. Q4Multiple choice1 mark
    Which of the following is the most reasonable guesstimate for the volume of a standard classroom?
    1. (a)20 m320\text{ m}^3
    2. (b)2000 m32000\text{ m}^3
    3. (c)200 m3200\text{ m}^3
    4. (d)20,000 m320,000\text{ m}^3
    Show answer and step marks
    1. Correct option: (c) 200 m3200\text{ m}^3+1
    Answer: (c)
  5. Q5Assertion and reason1 mark
    Assertion (A): If the edge of a cube is increased to 3 times its original length, its volume becomes 27 times. Reason (R): The volume of a cube of edge aa is given by V=a3V = a^3.
    1. (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
    2. (b)Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).
    3. (c)Assertion (A) is true but Reason (R) is false.
    4. (d)Assertion (A) is false but Reason (R) is true.
    Show answer and step marks
    1. Correct option: (a)+1
    Answer: (a)
  6. Q6Short answer3 marks
    A glass paperweight is shaped like a right pyramid with a square base of side 6 cm and vertical height 4 cm. The apex lies vertically above the centre of the square base. (a) Find the volume of the paperweight. [1] (b) Find the slant height of the pyramid, that is, the distance from the apex to the midpoint of a base edge. [1] (c) Find the lateral surface area of the pyramid, excluding the square base. [1]
    Show answer and step marks
    1. (a) Volume = (1/3) × base area × height = (1/3) × 6 × 6 × 4 = 48 cm³.+1
    2. (b) Half the base edge is 3 cm, so slant height = √(4² + 3²) = √25 = 5 cm.+1
    3. (c) Lateral area = 4 × (1/2) × 6 × 5 = 60 cm².+1
    Answer: (a) 48 cm³; (b) 5 cm; (c) 60 cm²

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