CBSE · Class 9 · Mathematics

Class 9 Predicting What Comes Next: Exploring Sequences and Progressions Mock Test (CBSE)

4 practice questions from Predicting What Comes Next: Exploring Sequences and Progressions, in the style of your board paper, each with a worked answer and the marks for every step. Then take a full chapter test on paper, snap the pages and get every step marked.

Topics in Predicting What Comes Next: Exploring Sequences and Progressions

  • Sequences
  • Explicit rule for a sequence
  • Recursive rule for a sequence
  • Arithmetic progressions
  • Sum of the first n natural numbers
  • Geometric progressions

Predicting What Comes Next: Exploring Sequences and Progressions practice questions with answers

  1. Q1Multiple choice1 mark
    What is the 10th term of the arithmetic progression 3,7,11,15,…3, 7, 11, 15, \dots?
    1. (a)39
    2. (b)37
    3. (c)41
    4. (d)35
    Show answer and step marks
    1. Correct option: (a) 3939, using a10=a+9d=3+9(4)=39a_{10} = a + 9d = 3 + 9(4) = 39.+1
    Answer: (a)
  2. Q2Multiple choice1 mark
    What is the sum of the first 20 natural numbers?
    1. (a)190
    2. (b)210
    3. (c)200
    4. (d)420
    Show answer and step marks
    1. Correct option: (b) 210210, using Sn=n(n+1)2=20(21)2=210S_n = \frac{n(n+1)}{2} = \frac{20(21)}{2} = 210.+1
    Answer: (b)
  3. Q3Multiple choice1 mark
    The explicit rule for the nth term of the sequence 3,7,11,15,…3, 7, 11, 15, \dots is:
    1. (a)4n−14n - 1
    2. (b)3n+13n + 1
    3. (c)4n+34n + 3
    4. (d)n+4n + 4
    Show answer and step marks
    1. Correct option: (a) 4n−14n - 1+1
    Answer: (a)
  4. Q4Short answer3 marks
    In an arithmetic progression, the 4th term is 14 and the 12th term is 70. Find the first term, the common difference, and the 20th term of this progression.
    Show answer and step marks
    1. Use an=a+(n−1)da_n = a + (n-1)d: a+3d=14a + 3d = 14 and a+11d=70a + 11d = 70; subtracting gives 8d=56  ⟹  d=78d = 56 \implies d = 7.+1
    2. Substitute to find the first term: a+3(7)=14  ⟹  a=−7a + 3(7) = 14 \implies a = -7.+1
    3. Calculate the 20th term: a20=−7+(20−1)(7)=−7+133=126a_{20} = -7 + (20-1)(7) = -7 + 133 = 126.+1
    Answer: First term is −7-7, common difference is 77, and the 20th term is 126126.

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