ICSE · Class 9 · Chemistry

Class 9 Atomic Structure and Chemical Bonding Mock Test (ICSE)

6 practice questions from Atomic Structure and Chemical Bonding, in the style of your board paper, each with a worked answer and the marks for every step. Then take a full chapter test on paper, snap the pages and get every step marked.

Topics in Atomic Structure and Chemical Bonding

  • Dalton's theory and its limitations
  • Thomson, Rutherford and Bohr models
  • Electronic configuration
  • Isotopes and isobars
  • Electrovalent bonding
  • Covalent bonding

Atomic Structure and Chemical Bonding practice questions with answers

  1. Q1Multiple choice1 mark
    Which of the following compounds is formed by the complete transfer of electrons and has a high melting point?
    1. (a)NaClNaCl
    2. (b)H2OH_2O
    3. (c)CCl4CCl_4
    4. (d)NH3NH_3
    Show answer and step marks
    1. Correct option: (a) NaClNaCl+1
    Answer: (a)
  2. Q2Multiple choice1 mark
    Which of the following postulates of Dalton's atomic theory was contradicted by the discovery of isotopes?
    1. (a)Atoms can neither be created nor destroyed.
    2. (b)All atoms of a given element are identical in mass and properties.
    3. (c)Compounds are formed by combination of atoms in a fixed ratio.
    4. (d)Atoms are indivisible.
    Show answer and step marks
    1. Correct option: (b) All atoms of a given element are identical in mass and properties.+1
    Answer: (b)
  3. Q3Multiple choice1 mark
    Rutherford's α\alpha-particle scattering experiment led directly to the discovery of the:
    1. (a)Atomic nucleus
    2. (b)Electron
    3. (c)Proton
    4. (d)Neutron
    Show answer and step marks
    1. Correct option: (a) Atomic nucleus+1
    Answer: (a)
  4. Q4Multiple choice1 mark
    The number of covalent bonds present in a molecule of nitrogen (N2\text{N}_2) gas is:
    1. (a)Two
    2. (b)Four
    3. (c)One
    4. (d)Three
    Show answer and step marks
    1. Correct option: (d) Three+1
    Answer: (d)
  5. Q5Long answer4 marks
    (a) Define the term isotopes. Name two common isotopes of hydrogen. (b) State why isotopes of an element have identical chemical properties. (c) Define isobars. Give one pair of isobars and state why they possess different chemical properties.
    Show answer and step marks
    1. (a) Isotopes are atoms of the same element having the same atomic number but different mass numbers.+0.5
    2. (a) First isotope of hydrogen named: protium (11H_1^1\text{H}), deuterium (12H_1^2\text{H}) or tritium (13H_1^3\text{H}).+0.5
    3. (a) Second isotope of hydrogen named, different from the first: protium, deuterium or tritium.+0.5
    4. (b) Isotopes have the same atomic number, hence the same number of electrons and the same electronic configuration (valence electrons), which decide chemical properties.+1
    5. (c) Isobars are atoms of different elements having different atomic numbers but the same mass number.+0.5
    6. (c) Pair of isobars, any one of: 1840Ar_{18}^{40}\text{Ar} and 2040Ca_{20}^{40}\text{Ca}; 1940K_{19}^{40}\text{K} and 2040Ca_{20}^{40}\text{Ca}; 614C_{6}^{14}\text{C} and 714N_{7}^{14}\text{N}; or any other valid pair of isobars.+0.5
    7. (c) Isobars have different atomic numbers, hence different numbers of electrons and different electronic configurations (valence electrons), so their chemical properties differ.+0.5
    Answer: (a) Isotopes are atoms of the same element with the same atomic number but different mass numbers; any two of protium (11H_1^1\text{H}), deuterium (12H_1^2\text{H}), tritium (13H_1^3\text{H}). (b) They have the same number of electrons and the same electronic configuration, which decides chemical properties. (c) Isobars are atoms of different elements with different atomic numbers but the same mass number, e.g. 1840Ar_{18}^{40}\text{Ar} and 2040Ca_{20}^{40}\text{Ca}; their different atomic numbers give different electronic configurations, so their chemical properties differ.
  6. Q6Long answer4 marks
    An element exists in two isotopic forms with mass numbers 3535 and 3737. Both have an atomic number of 1717. (a) Define isotopes and explain why these two atoms have identical chemical properties. (b) Calculate the number of protons, electrons, and neutrons in the isotope with mass number 3737.
    Show answer and step marks
    1. (a) Isotopes are atoms of the same element having the same atomic number but different mass numbers.+1
    2. (a) Both atoms have 1717 electrons and the same electronic configuration (2,8,72, 8, 7), hence the same valence electrons, so their chemical properties are identical.+1
    3. (b) Number of protons = atomic number = 1717.+0.5
    4. (b) Number of electrons = number of protons = 1717.+0.5
    5. (b) Number of neutrons = 37−17=2037 - 17 = 20.+1
    Answer: (a) Isotopes are atoms of the same element with the same atomic number but different mass numbers; both atoms have the same number of electrons and electronic configuration (2,8,72, 8, 7), so their chemical properties are identical. (b) Protons: 1717, Electrons: 1717, Neutrons: 2020.

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