ICSE · Class 10 · Mathematics

Class 10 Similarity Mock Test (ICSE)

4 practice questions from Similarity, in the style of your board paper, each with a worked answer and the marks for every step. Then take a full chapter test on paper, snap the pages and get every step marked.

Topics in Similarity

  • Similar triangles and criteria AA, SAS and SSS
  • Basic proportionality theorem
  • Areas of similar triangles
  • Applications to maps and models

Similarity practice questions with answers

  1. Q1Multiple choice1 mark
    In △ABC\triangle ABC and △DEF\triangle DEF, if ABDE=BCEF=CAFD\frac{AB}{DE} = \frac{BC}{EF} = \frac{CA}{FD}, then which of the following correctly expresses the similarity relationship?
    1. (a)△ABC∼△EFD\triangle ABC \sim \triangle EFD
    2. (b)△ABC∼△FED\triangle ABC \sim \triangle FED
    3. (c)△ABC∼△DEF\triangle ABC \sim \triangle DEF
    4. (d)△ABC∼△FDE\triangle ABC \sim \triangle FDE
    Show answer and step marks
    1. Correct option: (c) △ABC∼△DEF\triangle ABC \sim \triangle DEF+1
    Answer: (c)
  2. Q2Multiple choice1 mark
    If △DEF∼△XYZ\triangle DEF \sim \triangle XYZ such that area(△DEF)=81 cm2\text{area}(\triangle DEF) = 81\text{ cm}^2, area(△XYZ)=144 cm2\text{area}(\triangle XYZ) = 144\text{ cm}^2 and EF=6 cmEF = 6\text{ cm}, then the length of YZYZ is:
    1. (a)8 cm8\text{ cm}
    2. (b)6 cm6\text{ cm}
    3. (c)9 cm9\text{ cm}
    4. (d)7 cm7\text{ cm}
    Show answer and step marks
    1. Correct option: (a) 8 cm8\text{ cm}+1
    Answer: (a)
  3. Q3Multiple choice1 mark
    On a map drawn to a scale of 1:400001 : 40000, the distance between two railway stations is 3.5 cm3.5\text{ cm}. The actual distance between the stations in kilometres is:
    1. (a)0.14 km0.14\text{ km}
    2. (b)1.4 km1.4\text{ km}
    3. (c)140 km140\text{ km}
    4. (d)14 km14\text{ km}
    Show answer and step marks
    1. Correct option: (b) 1.4 km1.4\text{ km}+1
    Answer: (b)
  4. Q4Multiple choice1 mark
    In △ABC\triangle ABC, DE∥BCDE \parallel BC meets ABAB at DD and ACAC at EE. If AD=2.5 cmAD = 2.5\text{ cm}, DB=3.5 cmDB = 3.5\text{ cm} and AE=3 cmAE = 3\text{ cm}, then the length of ECEC is:
    1. (a)5.0 cm5.0\text{ cm}
    2. (b)3.2 cm3.2\text{ cm}
    3. (c)4.5 cm4.5\text{ cm}
    4. (d)4.2 cm4.2\text{ cm}
    Show answer and step marks
    1. Correct option: (d) 4.2 cm4.2\text{ cm}+1
    Answer: (d)

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  • 15 min10 marks
  • 30 min20 marks
  • 1.5 hr40 marks
  • 3 hr80 marks
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