CBSE · Class 10 · Mathematics

Class 10 Areas Related to Circles Mock Test (CBSE)

6 practice questions from Areas Related to Circles, in the style of your board paper, each with a worked answer and the marks for every step. Then take a full chapter test on paper, snap the pages and get every step marked.

Topics in Areas Related to Circles

  • Areas of sector and segment of a circle

Areas Related to Circles practice questions with answers

  1. Q1Assertion and reason1 mark
    Assertion (A): If the perimeter and the area of a circle are numerically equal, then the radius of the circle is 22 units. Reason (R): The area of a circle is πr2\pi r^2 and its perimeter is 2πr2\pi r.
    1. (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
    2. (b)Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).
    3. (c)Assertion (A) is true but Reason (R) is false.
    4. (d)Assertion (A) is false but Reason (R) is true.
    Show answer and step marks
    1. Correct option: (a) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A). Assertion calculation: 2πr=πr2  ⟹  r=22\pi r = \pi r^2 \implies r = 2, which is true. Reason states the correct formulas for area and perimeter, which directly explain the assertion.+1
    Answer: (a)
  2. Q2Multiple choice1 mark
    Find the area of a sector of a circle with radius 6 cm6\text{ cm} if the angle of the sector is 60∘60^\circ. (Use π=227\pi = \frac{22}{7})
    1. (a)1327 cm2\frac{132}{7}\text{ cm}^2
    2. (b)667 cm2\frac{66}{7}\text{ cm}^2
    3. (c)13214 cm2\frac{132}{14}\text{ cm}^2
    4. (d)2647 cm2\frac{264}{7}\text{ cm}^2
    Show answer and step marks
    1. Area = 60∘360∘×227×62=1327 cm2\frac{60^\circ}{360^\circ} \times \frac{22}{7} \times 6^2 = \frac{132}{7}\text{ cm}^2+1
    Answer: (a)
  3. Q3Assertion and reason1 mark
    Assertion (A): For a circle of radius 7 cm7\text{ cm}, the area of the minor segment cut off by a chord that subtends 90∘90^\circ at the centre is less than the area of the corresponding minor sector. Reason (R): The area of a sector of a circle is directly proportional to its central angle.
    1. (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
    2. (b)Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).
    3. (c)Assertion (A) is true but Reason (R) is false.
    4. (d)Assertion (A) is false but Reason (R) is true.
    Show answer and step marks
    1. Correct option: (b) Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A). Sector area is 90360×π×72=38.5 cm2\frac{90}{360} \times \pi \times 7^2 = 38.5\text{ cm}^2 and the triangle formed by the two radii and the chord has area 12×7×7=24.5 cm2\frac{1}{2} \times 7 \times 7 = 24.5\text{ cm}^2, so the segment is 14 cm214\text{ cm}^2, which is less than 38.5 cm238.5\text{ cm}^2. The reason is true, but it does not explain why the segment is smaller than the sector.+1
    Answer: (b)
  4. Q4Multiple choice1 mark
    The perimeter of a protractor is 72 cm72\text{ cm}. Its diameter is: (Use π=227\pi = \frac{22}{7})
    1. (a)14 cm14\text{ cm}
    2. (b)28 cm28\text{ cm}
    3. (c)36 cm36\text{ cm}
    4. (d)56 cm56\text{ cm}
    Show answer and step marks
    1. Correct option: (b) 28 cm28\text{ cm}. Perimeter = 18d7=72  ⟹  d=28 cm\frac{18d}{7} = 72 \implies d = 28\text{ cm}+1
    Answer: (b)
  5. Q5Multiple choice1 mark
    A sector of a circle of radius 14 cm14\text{ cm} subtends an angle of 45∘45^\circ at the centre. Taking π=227\pi = \frac{22}{7}, the area of the sector is:
    1. (a)38.5 cm238.5\text{ cm}^2
    2. (b)154 cm2154\text{ cm}^2
    3. (c)77 cm277\text{ cm}^2
    4. (d)308 cm2308\text{ cm}^2
    Show answer and step marks
    1. Correct option: (c) 77 cm277\text{ cm}^2, since area of sector =45360×227×14×14=18×616=77 cm2=\frac{45}{360}\times\frac{22}{7}\times 14\times 14=\frac{1}{8}\times 616=77\text{ cm}^2.+1
    Answer: (c)
  6. Q6Assertion and reason1 mark
    Assertion (A): If the area of a circle is 154 cm2154\text{ cm}^2, then its perimeter is 44 cm44\text{ cm} (take π=227\pi = \frac{22}{7}). Reason (R): The perimeter (circumference) of a circle is given by the formula 2πr2\pi r.
    1. (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
    2. (b)Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).
    3. (c)Assertion (A) is true but Reason (R) is false.
    4. (d)Assertion (A) is false but Reason (R) is true.
    Show answer and step marks
    1. Correct option: (a) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A). Both Assertion and Reason are true, and Reason correctly explains Assertion.+1
    Answer: (a)

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